(10x-45)=(6x-1)

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Solution for (10x-45)=(6x-1) equation: 



(10x-45)=(6x-1)

We move all terms to the left:

(10x-45)-((6x-1))=0

We get rid of parentheses

10x-((6x-1))-45=0



We calculate terms in parentheses: -((6x-1)), so:

(6x-1)

We get rid of parentheses

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

10x-6x+1-45=0

We add all the numbers together, and all the variables

4x-44=0

We move all terms containing x to the left, all other terms to the right

4x=44

x=44/4

x=11

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