(10x-4x+7)+(6x-8)=(10-4x-2x)

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Solution for (10x-4x+7)+(6x-8)=(10-4x-2x) equation: 



(10x-4x+7)+(6x-8)=(10-4x-2x)

We move all terms to the left:

(10x-4x+7)+(6x-8)-((10-4x-2x))=0

We add all the numbers together, and all the variables

(6x+7)+(6x-8)-((-6x+10))=0

We get rid of parentheses

6x+6x-((-6x+10))+7-8=0



We calculate terms in parentheses: -((-6x+10)), so:

(-6x+10)

We get rid of parentheses

-6x+10

Back to the equation:

-(-6x+10)



We add all the numbers together, and all the variables

12x-(-6x+10)-1=0

We get rid of parentheses

12x+6x-10-1=0

We add all the numbers together, and all the variables

18x-11=0

We move all terms containing x to the left, all other terms to the right

18x=11

x=11/18

x=11/18

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