(10x-5)+(3x+29)=180

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Solution for (10x-5)+(3x+29)=180 equation: 



(10x-5)+(3x+29)=180

We move all terms to the left:

(10x-5)+(3x+29)-(180)=0

We get rid of parentheses

10x+3x-5+29-180=0

We add all the numbers together, and all the variables

13x-156=0

We move all terms containing x to the left, all other terms to the right

13x=156

x=156/13

x=12

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