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(10x-7)(3x+7)=0
We multiply parentheses ..
(+30x^2+70x-21x-49)=0
We get rid of parentheses
30x^2+70x-21x-49=0
We add all the numbers together, and all the variables
30x^2+49x-49=0
a = 30; b = 49; c = -49;
Δ = b2-4ac
Δ = 492-4·30·(-49)
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8281}=91$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-91}{2*30}=\frac{-140}{60} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+91}{2*30}=\frac{42}{60} =7/10 $
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