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(10x-7)(4x+6)=5x
We move all terms to the left:
(10x-7)(4x+6)-(5x)=0
We add all the numbers together, and all the variables
-5x+(10x-7)(4x+6)=0
We multiply parentheses ..
(+40x^2+60x-28x-42)-5x=0
We get rid of parentheses
40x^2+60x-28x-5x-42=0
We add all the numbers together, and all the variables
40x^2+27x-42=0
a = 40; b = 27; c = -42;
Δ = b2-4ac
Δ = 272-4·40·(-42)
Δ = 7449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{7449}}{2*40}=\frac{-27-\sqrt{7449}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{7449}}{2*40}=\frac{-27+\sqrt{7449}}{80} $
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