(10x-7)/15x=(2x+3)/3x

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Solution for (10x-7)/15x=(2x+3)/3x equation: 



(10x-7)/15x=(2x+3)/3x

We move all terms to the left:

(10x-7)/15x-((2x+3)/3x)=0



Domain of the equation: 15x!=0

x!=0/15

x!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(10x-7)*3x)/45x^2+(-((2x+3)*15x)/45x^2=0

We calculate fractions


((10x-7)*3x)*45x^2)/(45x^2+(*45x^2)+(-((2x+3)*15x)*45x^2)/(45x^2+(*45x^2)=0



We calculate terms in parentheses: +(-((2x+3)*15x)*45x^2)/(45x^2+(*45x^2), so:

-((2x+3)*15x)*45x^2)/(45x^2+(*45x^2

We multiply all the terms by the denominator


-((2x+3)*15x)*45x^2)+((*45x^2)*(45x^2

Back to the equation:

+(-((2x+3)*15x)*45x^2)+((*45x^2)*(45x^2)



We get rid of parentheses

((10x-7)*3x)*45x^2)/(45x^2+*45x^2+(-((2x+3)*15x)*45x^2)+((*45x^2)*45x^2=0

We multiply all the terms by the denominator


((10x-7)*3x)*45x^2)+(*45x^2)*(45x^2+((-((2x+3)*15x)*45x^2))*(45x^2+(((*45x^2)*45x^2)*(45x^2=0

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