(10x-89)+(6x-19)=180

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Solution for (10x-89)+(6x-19)=180 equation: 



(10x-89)+(6x-19)=180

We move all terms to the left:

(10x-89)+(6x-19)-(180)=0

We get rid of parentheses

10x+6x-89-19-180=0

We add all the numbers together, and all the variables

16x-288=0

We move all terms containing x to the left, all other terms to the right

16x=288

x=288/16

x=18

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