(10x/x+5)(x2-2x-35/2x)

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Solution for (10x/x+5)(x2-2x-35/2x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((10*x)/x+5)*(x^2-(2*x)-((35/2)*x)) = 0

((10*x)/x+5)*(x^2-2*x+(-35/2)*x) = 0

15*(x^2-39/2*x) = 0

x^2-39/2*x = 0

x*(x-39/2) = 0

x-39/2 = 0 // + 39/2

x = 39/2

x*(x-39/2) = 0

15*x*(x-39/2) = 0

( x-39/2 )

x-39/2 = 0 // + 39/2

x = 39/2

( x )

x = 0

x in { 0} 

x = 39/2

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