(10y)=(3y-2)

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Solution for (10y)=(3y-2) equation: 



(10y)=(3y-2)

We move all terms to the left:

(10y)-((3y-2))=0



We calculate terms in parentheses: -((3y-2)), so:

(3y-2)

We get rid of parentheses

3y-2

Back to the equation:

-(3y-2)



We get rid of parentheses

10y-3y+2=0

We add all the numbers together, and all the variables

7y+2=0

We move all terms containing y to the left, all other terms to the right

7y=-2

y=-2/7

y=-2/7

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