(10y-89)=(4y-11)

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Solution for (10y-89)=(4y-11) equation: 



(10y-89)=(4y-11)

We move all terms to the left:

(10y-89)-((4y-11))=0

We get rid of parentheses

10y-((4y-11))-89=0



We calculate terms in parentheses: -((4y-11)), so:

(4y-11)

We get rid of parentheses

4y-11

Back to the equation:

-(4y-11)



We get rid of parentheses

10y-4y+11-89=0

We add all the numbers together, and all the variables

6y-78=0

We move all terms containing y to the left, all other terms to the right

6y=78

y=78/6

y=13

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