(11(y-10))=(4y-5)

Solution for (11(y-10))=(4y-5) equation:

(11(y-10))=(4y-5)

We move all terms to the left:

(11(y-10))-((4y-5))=0


We calculate terms in parentheses: +(11(y-10)), so:

11(y-10)

We multiply parentheses

11y-110

Back to the equation:

+(11y-110)



We calculate terms in parentheses: -((4y-5)), so:

(4y-5)

We get rid of parentheses

4y-5

Back to the equation:

-(4y-5)


We get rid of parentheses

11y-4y-110+5=0

We add all the numbers together, and all the variables

7y-105=0

We move all terms containing y to the left, all other terms to the right

7y=105

y=105/7

y=15