(11-2x)(6-2x)=126

Solution for (11-2x)(6-2x)=126 equation:

(11-2x)(6-2x)=126

We move all terms to the left:

(11-2x)(6-2x)-(126)=0

We add all the numbers together, and all the variables

(-2x+11)(-2x+6)-126=0

We multiply parentheses ..

(+4x^2-12x-22x+66)-126=0

We get rid of parentheses

4x^2-12x-22x+66-126=0

We add all the numbers together, and all the variables

4x^2-34x-60=0

a = 4; b = -34; c = -60;
Δ = b2-4ac
Δ = -342-4·4·(-60)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-46}{2*4}=\frac{-12}{8}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+46}{2*4}=\frac{80}{8}
=10
$