(11/15x-21)-(2/5x+16)=0

Solution for (11/15x-21)-(2/5x+16)=0 equation:

(11/15x-21)-(2/5x+16)=0


Domain of the equation: 15x-21)!=0

x∈R



Domain of the equation: 5x+16)!=0

x∈R


We get rid of parentheses

11/15x-2/5x-21-16=0

We calculate fractions


55x/75x^2+(-30x)/75x^2-21-16=0

We add all the numbers together, and all the variables

55x/75x^2+(-30x)/75x^2-37=0

We multiply all the terms by the denominator


55x+(-30x)-37*75x^2=0

Wy multiply elements

-2775x^2+55x+(-30x)=0

We get rid of parentheses

-2775x^2+55x-30x=0

We add all the numbers together, and all the variables

-2775x^2+25x=0

a = -2775; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-2775)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-2775}=\frac{-50}{-5550}
=1/111
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-2775}=\frac{0}{-5550}
=0
$