(11/2)p+7=(3/2)p+35

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Solution for (11/2)p+7=(3/2)p+35 equation: 



(11/2)p+7=(3/2)p+35

We move all terms to the left:

(11/2)p+7-((3/2)p+35)=0



Domain of the equation: 2)p!=0

p!=0/1

p!=0

p∈R





Domain of the equation: 2)p+35)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

(+11/2)p-((+3/2)p+35)+7=0

We multiply parentheses

11p^2-((+3/2)p+35)+7=0

We multiply all the terms by the denominator


11p^2*2)p+35)-((+7*2)p+35)+3=0

We add all the numbers together, and all the variables

11p^2*2)p+35)-(14p+35)+3=0

Wy multiply elements

22p^3=0

We do not support eppression: p^3

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