(11/3)+3n=(4/5n)+18

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Solution for (11/3)+3n=(4/5n)+18 equation: 



(11/3)+3n=(4/5n)+18

We move all terms to the left:

(11/3)+3n-((4/5n)+18)=0



Domain of the equation: 5n)+18)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

3n-((+4/5n)+18)+(+11/3)=0

We get rid of parentheses

3n-((+4/5n)+18)+11/3=0

We calculate fractions


3n+()/5n+18)*3)+55n/5n+18)*3)=0

We calculate fractions


3n+(()*5n)/25n^2+18*3)+55n*5n)/25n^2=0

We multiply all the terms by the denominator


3n*25n^2+(()*5n)+18*3)+55n*5n)=0



We calculate terms in parentheses: +(()*5n), so:

()*5n



Wy multiply elements

75n^3+270n^2+(()*5n)=0



We calculate terms in parentheses: +(()*5n), so:

()*5n



We do not support enpression: n^3

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