(11/4x-10)+(3/4x+20)=180

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Solution for (11/4x-10)+(3/4x+20)=180 equation: 



(11/4x-10)+(3/4x+20)=180

We move all terms to the left:

(11/4x-10)+(3/4x+20)-(180)=0



Domain of the equation: 4x-10)!=0

x∈R





Domain of the equation: 4x+20)!=0

x∈R



We get rid of parentheses

11/4x+3/4x-10+20-180=0

We multiply all the terms by the denominator


-10*4x+20*4x-180*4x+11+3=0

We add all the numbers together, and all the variables

-10*4x+20*4x-180*4x+14=0

Wy multiply elements

-40x+80x-720x+14=0

We add all the numbers together, and all the variables

-680x+14=0

We move all terms containing x to the left, all other terms to the right

-680x=-14

x=-14/-680

x=7/340

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