(11/4x-10)+(3/4x+20)=90

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Solution for (11/4x-10)+(3/4x+20)=90 equation: 



(11/4x-10)+(3/4x+20)=90

We move all terms to the left:

(11/4x-10)+(3/4x+20)-(90)=0



Domain of the equation: 4x-10)!=0

x∈R





Domain of the equation: 4x+20)!=0

x∈R



We get rid of parentheses

11/4x+3/4x-10+20-90=0

We multiply all the terms by the denominator


-10*4x+20*4x-90*4x+11+3=0

We add all the numbers together, and all the variables

-10*4x+20*4x-90*4x+14=0

Wy multiply elements

-40x+80x-360x+14=0

We add all the numbers together, and all the variables

-320x+14=0

We move all terms containing x to the left, all other terms to the right

-320x=-14

x=-14/-320

x=7/160

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