(11/5)b-2=(3/5)b+10

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Solution for (11/5)b-2=(3/5)b+10 equation: 



(11/5)b-2=(3/5)b+10

We move all terms to the left:

(11/5)b-2-((3/5)b+10)=0



Domain of the equation: 5)b!=0

b!=0/1

b!=0

b∈R





Domain of the equation: 5)b+10)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+11/5)b-((+3/5)b+10)-2=0

We multiply parentheses

11b^2-((+3/5)b+10)-2=0

We multiply all the terms by the denominator


11b^2*5)b+10)-((-2*5)b+10)+3=0

We add all the numbers together, and all the variables

11b^2*5)b+10)-((-10)b+10)+3=0

Wy multiply elements

55b^3-10)b+10)+3=0

We do not support ebpression: b^3

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