(11/x)=(-5/3x)+1

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Solution for (11/x)=(-5/3x)+1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

11/x = (-5/3)*x+1 // - (-5/3)*x+1

11/x-((-5/3)*x)-1 = 0

(5/3)*x+11/x-1 = 0

5/3*x^1+11*x^-1-1*x^0 = 0

(5/3*x^2-1*x^1+11*x^0)/(x^1) = 0 // * x^2

x^1*(5/3*x^2-1*x^1+11*x^0) = 0

x^1

(5/3)*x^2-x+11 = 0

(5/3)*x^2-x+11 = 0

DELTA = (-1)^2-(4*11*(5/3))

DELTA = -217/3

DELTA < 0

x in { } 

x belongs to the empty set

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