(117+105+112+x)/4=115

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Solution for (117+105+112+x)/4=115 equation: 



(117+105+112+x)/4=115

We move all terms to the left:

(117+105+112+x)/4-(115)=0

We add all the numbers together, and all the variables

(x+334)/4-115=0

We multiply all the terms by the denominator


(x+334)-115*4=0

We add all the numbers together, and all the variables

(x+334)-460=0

We get rid of parentheses

x+334-460=0

We add all the numbers together, and all the variables

x-126=0

We move all terms containing x to the left, all other terms to the right

x=126

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