(11b-11)/5=3b-2

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Solution for (11b-11)/5=3b-2 equation: 


b in (-oo:+oo)

(11*b-11)/5 = 3*b-2 // - 3*b-2

(11*b-11)/5-(3*b)+2 = 0

(11*b-11)/5-3*b+2 = 0

(11*b-11)/5+(-3*5*b)/5+(2*5)/5 = 0

11*b-3*5*b+2*5-11 = 0

10-4*b-11 = 0

-4*b-1 = 0

(-4*b-1)/5 = 0

(-4*b-1)/5 = 0 // * 5

-4*b-1 = 0

-4*b-1 = 0 // + 1

-4*b = 1 // : -4

b = 1/(-4)

b = -1/4

b = -1/4

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