(11t+5)(6t+18)=0

Solution for (11t+5)(6t+18)=0 equation:

(11t+5)(6t+18)=0

We multiply parentheses ..

(+66t^2+198t+30t+90)=0

We get rid of parentheses

66t^2+198t+30t+90=0

We add all the numbers together, and all the variables

66t^2+228t+90=0

a = 66; b = 228; c = +90;
Δ = b2-4ac
Δ = 2282-4·66·90
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(228)-168}{2*66}=\frac{-396}{132}
=-3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(228)+168}{2*66}=\frac{-60}{132}
=-5/11
$