(11t-5)(6t-5)=0

Solution for (11t-5)(6t-5)=0 equation:

(11t-5)(6t-5)=0

We multiply parentheses ..

(+66t^2-55t-30t+25)=0

We get rid of parentheses

66t^2-55t-30t+25=0

We add all the numbers together, and all the variables

66t^2-85t+25=0

a = 66; b = -85; c = +25;
Δ = b2-4ac
Δ = -852-4·66·25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-25}{2*66}=\frac{60}{132}
=5/11
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+25}{2*66}=\frac{110}{132}
=5/6
$