(11t/28)-(t-4)=1

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Solution for (11t/28)-(t-4)=1 equation:



(11t/28)-(t-4)=1
We move all terms to the left:
(11t/28)-(t-4)-(1)=0
We add all the numbers together, and all the variables
(+11t/28)-(t-4)-1=0
We get rid of parentheses
11t/28-t+4-1=0
We multiply all the terms by the denominator
11t-t*28+4*28-1*28=0
We add all the numbers together, and all the variables
11t-t*28+84=0
Wy multiply elements
11t-28t+84=0
We add all the numbers together, and all the variables
-17t+84=0
We move all terms containing t to the left, all other terms to the right
-17t=-84
t=-84/-17
t=4+16/17

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