(11x)(-9x)=99x

Solution for (11x)(-9x)=99x equation:

(11x)(-9x)=99x

We move all terms to the left:

(11x)(-9x)-(99x)=0

We add all the numbers together, and all the variables

-99x+11x(-9x)=0

We multiply parentheses

-99x^2-99x=0

a = -99; b = -99; c = 0;
Δ = b2-4ac
Δ = -992-4·(-99)·0
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-99}{2*-99}=\frac{0}{-198}
=0$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+99}{2*-99}=\frac{198}{-198}
=-1$