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(11x+)(6x+5)+90=180
We move all terms to the left:
(11x+)(6x+5)+90-(180)=0
We add all the numbers together, and all the variables
(+11x)(6x+5)+90-180=0
We add all the numbers together, and all the variables
(+11x)(6x+5)-90=0
We multiply parentheses ..
(+66x^2+55x)-90=0
We get rid of parentheses
66x^2+55x-90=0
a = 66; b = 55; c = -90;
Δ = b2-4ac
Δ = 552-4·66·(-90)
Δ = 26785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{26785}}{2*66}=\frac{-55-\sqrt{26785}}{132} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{26785}}{2*66}=\frac{-55+\sqrt{26785}}{132} $
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