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(11x+1)(12x+13)=24
We move all terms to the left:
(11x+1)(12x+13)-(24)=0
We multiply parentheses ..
(+132x^2+143x+12x+13)-24=0
We get rid of parentheses
132x^2+143x+12x+13-24=0
We add all the numbers together, and all the variables
132x^2+155x-11=0
a = 132; b = 155; c = -11;
Δ = b2-4ac
Δ = 1552-4·132·(-11)
Δ = 29833
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(155)-\sqrt{29833}}{2*132}=\frac{-155-\sqrt{29833}}{264} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(155)+\sqrt{29833}}{2*132}=\frac{-155+\sqrt{29833}}{264} $
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