(11x+10)+(8x+5)=(4x-5)

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Solution for (11x+10)+(8x+5)=(4x-5) equation: 



(11x+10)+(8x+5)=(4x-5)

We move all terms to the left:

(11x+10)+(8x+5)-((4x-5))=0

We get rid of parentheses

11x+8x-((4x-5))+10+5=0



We calculate terms in parentheses: -((4x-5)), so:

(4x-5)

We get rid of parentheses

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

19x-(4x-5)+15=0

We get rid of parentheses

19x-4x+5+15=0

We add all the numbers together, and all the variables

15x+20=0

We move all terms containing x to the left, all other terms to the right

15x=-20

x=-20/15

x=-1+1/3

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