(11x+35)=(20x-28)

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Solution for (11x+35)=(20x-28) equation: 



(11x+35)=(20x-28)

We move all terms to the left:

(11x+35)-((20x-28))=0

We get rid of parentheses

11x-((20x-28))+35=0



We calculate terms in parentheses: -((20x-28)), so:

(20x-28)

We get rid of parentheses

20x-28

Back to the equation:

-(20x-28)



We get rid of parentheses

11x-20x+28+35=0

We add all the numbers together, and all the variables

-9x+63=0

We move all terms containing x to the left, all other terms to the right

-9x=-63

x=-63/-9

x=+7

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