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(11x+4)(2x+4)=90
We move all terms to the left:
(11x+4)(2x+4)-(90)=0
We multiply parentheses ..
(+22x^2+44x+8x+16)-90=0
We get rid of parentheses
22x^2+44x+8x+16-90=0
We add all the numbers together, and all the variables
22x^2+52x-74=0
a = 22; b = 52; c = -74;
Δ = b2-4ac
Δ = 522-4·22·(-74)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-96}{2*22}=\frac{-148}{44} =-3+4/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+96}{2*22}=\frac{44}{44} =1 $
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