(11x+9)(4x+5)=298

Solution for (11x+9)(4x+5)=298 equation:

(11x+9)(4x+5)=298

We move all terms to the left:

(11x+9)(4x+5)-(298)=0

We multiply parentheses ..

(+44x^2+55x+36x+45)-298=0

We get rid of parentheses

44x^2+55x+36x+45-298=0

We add all the numbers together, and all the variables

44x^2+91x-253=0

a = 44; b = 91; c = -253;
Δ = b2-4ac
Δ = 912-4·44·(-253)
Δ = 52809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-\sqrt{52809}}{2*44}=\frac{-91-\sqrt{52809}}{88}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+\sqrt{52809}}{2*44}=\frac{-91+\sqrt{52809}}{88}
$