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(11x-10)+(9x^2)=180
We move all terms to the left:
(11x-10)+(9x^2)-(180)=0
determiningTheFunctionDomain 9x^2+(11x-10)-180=0
We get rid of parentheses
9x^2+11x-10-180=0
We add all the numbers together, and all the variables
9x^2+11x-190=0
a = 9; b = 11; c = -190;
Δ = b2-4ac
Δ = 112-4·9·(-190)
Δ = 6961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{6961}}{2*9}=\frac{-11-\sqrt{6961}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{6961}}{2*9}=\frac{-11+\sqrt{6961}}{18} $
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