(11x-12)(2x+10)=180

Solution for (11x-12)(2x+10)=180 equation:

(11x-12)(2x+10)=180

We move all terms to the left:

(11x-12)(2x+10)-(180)=0

We multiply parentheses ..

(+22x^2+110x-24x-120)-180=0

We get rid of parentheses

22x^2+110x-24x-120-180=0

We add all the numbers together, and all the variables

22x^2+86x-300=0

a = 22; b = 86; c = -300;
Δ = b2-4ac
Δ = 862-4·22·(-300)
Δ = 33796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{33796}=\sqrt{4*8449}=\sqrt{4}*\sqrt{8449}=2\sqrt{8449}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-2\sqrt{8449}}{2*22}=\frac{-86-2\sqrt{8449}}{44}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+2\sqrt{8449}}{2*22}=\frac{-86+2\sqrt{8449}}{44}
$