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(11x-12)(2x+10)=180
We move all terms to the left:
(11x-12)(2x+10)-(180)=0
We multiply parentheses ..
(+22x^2+110x-24x-120)-180=0
We get rid of parentheses
22x^2+110x-24x-120-180=0
We add all the numbers together, and all the variables
22x^2+86x-300=0
a = 22; b = 86; c = -300;
Δ = b2-4ac
Δ = 862-4·22·(-300)
Δ = 33796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{33796}=\sqrt{4*8449}=\sqrt{4}*\sqrt{8449}=2\sqrt{8449}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-2\sqrt{8449}}{2*22}=\frac{-86-2\sqrt{8449}}{44} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+2\sqrt{8449}}{2*22}=\frac{-86+2\sqrt{8449}}{44} $
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