(11x-2)(3x-4)=0

Solution for (11x-2)(3x-4)=0 equation:

(11x-2)(3x-4)=0

We multiply parentheses ..

(+33x^2-44x-6x+8)=0

We get rid of parentheses

33x^2-44x-6x+8=0

We add all the numbers together, and all the variables

33x^2-50x+8=0

a = 33; b = -50; c = +8;
Δ = b2-4ac
Δ = -502-4·33·8
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-38}{2*33}=\frac{12}{66}
=2/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+38}{2*33}=\frac{88}{66}
=1+1/3
$