(11x-2)+19x+3)+(9x+1)=180

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Solution for (11x-2)+19x+3)+(9x+1)=180 equation: 



(11x-2)+19x+3)+(9x+1)=180

We move all terms to the left:

(11x-2)+19x+3)+(9x+1)-(180)=0

We add all the numbers together, and all the variables

19x+(11x-2)+3)+(9x=0

We get rid of parentheses

19x+11x+3)+(9x-2=0

We add all the numbers together, and all the variables

30x+3)+(9x-2=0

We move all terms containing x to the left, all other terms to the right

30x+3)+(9x=2

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