(11x-20)(2x-2)=144

Solution for (11x-20)(2x-2)=144 equation:

(11x-20)(2x-2)=144

We move all terms to the left:

(11x-20)(2x-2)-(144)=0

We multiply parentheses ..

(+22x^2-22x-40x+40)-144=0

We get rid of parentheses

22x^2-22x-40x+40-144=0

We add all the numbers together, and all the variables

22x^2-62x-104=0

a = 22; b = -62; c = -104;
Δ = b2-4ac
Δ = -622-4·22·(-104)
Δ = 12996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12996}=114$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-114}{2*22}=\frac{-52}{44}
=-1+2/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+114}{2*22}=\frac{176}{44}
=4
$