(11x-31)=(8x+20)

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Solution for (11x-31)=(8x+20) equation: 



(11x-31)=(8x+20)

We move all terms to the left:

(11x-31)-((8x+20))=0

We get rid of parentheses

11x-((8x+20))-31=0



We calculate terms in parentheses: -((8x+20)), so:

(8x+20)

We get rid of parentheses

8x+20

Back to the equation:

-(8x+20)



We get rid of parentheses

11x-8x-20-31=0

We add all the numbers together, and all the variables

3x-51=0

We move all terms containing x to the left, all other terms to the right

3x=51

x=51/3

x=17

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