(11x-5)=(100-4x)

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Solution for (11x-5)=(100-4x) equation: 



(11x-5)=(100-4x)

We move all terms to the left:

(11x-5)-((100-4x))=0

We add all the numbers together, and all the variables

(11x-5)-((-4x+100))=0

We get rid of parentheses

11x-((-4x+100))-5=0



We calculate terms in parentheses: -((-4x+100)), so:

(-4x+100)

We get rid of parentheses

-4x+100

Back to the equation:

-(-4x+100)



We get rid of parentheses

11x+4x-100-5=0

We add all the numbers together, and all the variables

15x-105=0

We move all terms containing x to the left, all other terms to the right

15x=105

x=105/15

x=7

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