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(11y+3)+(5y+1)=116
We move all terms to the left:
(11y+3)+(5y+1)-(116)=0
We get rid of parentheses
11y+5y+3+1-116=0
We add all the numbers together, and all the variables
16y-112=0
We move all terms containing y to the left, all other terms to the right
16y=112
y=112/16
y=7
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