(11z+2)+(6z+4)+(z+5)=90

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Solution for (11z+2)+(6z+4)+(z+5)=90 equation: 



(11z+2)+(6z+4)+(z+5)=90

We move all terms to the left:

(11z+2)+(6z+4)+(z+5)-(90)=0

We get rid of parentheses

11z+6z+z+2+4+5-90=0

We add all the numbers together, and all the variables

18z-79=0

We move all terms containing z to the left, all other terms to the right

18z=79

z=79/18

z=4+7/18

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