(12)(3x)(2x+1)=10800

Solution for (12)(3x)(2x+1)=10800 equation:

(12)(3x)(2x+1)=10800

We move all terms to the left:

(12)(3x)(2x+1)-(10800)=0

We multiply parentheses

246x^2+123x-10800=0

a = 246; b = 123; c = -10800;
Δ = b2-4ac
Δ = 1232-4·246·(-10800)
Δ = 10642329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10642329}=\sqrt{9*1182481}=\sqrt{9}*\sqrt{1182481}=3\sqrt{1182481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(123)-3\sqrt{1182481}}{2*246}=\frac{-123-3\sqrt{1182481}}{492}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(123)+3\sqrt{1182481}}{2*246}=\frac{-123+3\sqrt{1182481}}{492}
$