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(12)2/3x+7x=90
We move all terms to the left:
(12)2/3x+7x-(90)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
7x+122/3x-90=0
We multiply all the terms by the denominator
7x*3x-90*3x+122=0
Wy multiply elements
21x^2-270x+122=0
a = 21; b = -270; c = +122;
Δ = b2-4ac
Δ = -2702-4·21·122
Δ = 62652
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{62652}=\sqrt{4*15663}=\sqrt{4}*\sqrt{15663}=2\sqrt{15663}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-270)-2\sqrt{15663}}{2*21}=\frac{270-2\sqrt{15663}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-270)+2\sqrt{15663}}{2*21}=\frac{270+2\sqrt{15663}}{42} $
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