(12+20x)=(4+22x)

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Solution for (12+20x)=(4+22x) equation: 



(12+20x)=(4+22x)

We move all terms to the left:

(12+20x)-((4+22x))=0

We add all the numbers together, and all the variables

(20x+12)-((22x+4))=0

We get rid of parentheses

20x-((22x+4))+12=0



We calculate terms in parentheses: -((22x+4)), so:

(22x+4)

We get rid of parentheses

22x+4

Back to the equation:

-(22x+4)



We get rid of parentheses

20x-22x-4+12=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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