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(12+4x)(x)=352
We move all terms to the left:
(12+4x)(x)-(352)=0
We add all the numbers together, and all the variables
(4x+12)x-352=0
We multiply parentheses
4x^2+12x-352=0
a = 4; b = 12; c = -352;
Δ = b2-4ac
Δ = 122-4·4·(-352)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-76}{2*4}=\frac{-88}{8} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+76}{2*4}=\frac{64}{8} =8 $
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