(12+z+-3y)-y+2z=4

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Solution for (12+z+-3y)-y+2z=4 equation:


Simplifying
(12 + z + -3y) + -1y + 2z = 4

Reorder the terms:
(12 + -3y + z) + -1y + 2z = 4

Remove parenthesis around (12 + -3y + z)
12 + -3y + z + -1y + 2z = 4

Reorder the terms:
12 + -3y + -1y + z + 2z = 4

Combine like terms: -3y + -1y = -4y
12 + -4y + z + 2z = 4

Combine like terms: z + 2z = 3z
12 + -4y + 3z = 4

Solving
12 + -4y + 3z = 4

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -4y + -12 + 3z = 4 + -12

Reorder the terms:
12 + -12 + -4y + 3z = 4 + -12

Combine like terms: 12 + -12 = 0
0 + -4y + 3z = 4 + -12
-4y + 3z = 4 + -12

Combine like terms: 4 + -12 = -8
-4y + 3z = -8

Add '-3z' to each side of the equation.
-4y + 3z + -3z = -8 + -3z

Combine like terms: 3z + -3z = 0
-4y + 0 = -8 + -3z
-4y = -8 + -3z

Divide each side by '-4'.
y = 2 + 0.75z

Simplifying
y = 2 + 0.75z

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