(12,-2)(5,-10)=(-4,10)(4,y)

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Solution for (12,-2)(5,-10)=(-4,10)(4,y) equation: 



(12.-2)(5.-10)=(-4.10)(4.y)

We move all terms to the left:

(12.-2)(5.-10)-((-4.10)(4.y))=0

We add all the numbers together, and all the variables

-((-4.1)(+4.y))+10(-5)=0

We add all the numbers together, and all the variables

-((-4.1)(+4.y))-50=0

We multiply parentheses ..

-((-16.4y))-50=0



We calculate terms in parentheses: -((-16.4y)), so:

(-16.4y)

We get rid of parentheses

-16.4y

Back to the equation:

-(-16.4y)



We get rid of parentheses

16.4y-50=0

We move all terms containing y to the left, all other terms to the right

16.4y=50

y=50/16.4

y=3+0.8/16.4

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