(12-2x)(10-2x)=V

Solution for (12-2x)(10-2x)=V equation:

(12-2x)(10-2x)=

We move all terms to the left:

(12-2x)(10-2x)-()=0

We add all the numbers together, and all the variables

(-2x+12)(-2x+10)-()=0

We add all the numbers together, and all the variables

(-2x+12)(-2x+10)=0

We multiply parentheses ..

(+4x^2-20x-24x+120)=0

We get rid of parentheses

4x^2-20x-24x+120=0

We add all the numbers together, and all the variables

4x^2-44x+120=0

a = 4; b = -44; c = +120;
Δ = b2-4ac
Δ = -442-4·4·120
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-4}{2*4}=\frac{40}{8}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+4}{2*4}=\frac{48}{8}
=6
$