(12-2x)(12-x)=0

Solution for (12-2x)(12-x)=0 equation:

(12-2x)(12-x)=0

We add all the numbers together, and all the variables

(-2x+12)(-1x+12)=0

We multiply parentheses ..

(+2x^2-24x-12x+144)=0

We get rid of parentheses

2x^2-24x-12x+144=0

We add all the numbers together, and all the variables

2x^2-36x+144=0

a = 2; b = -36; c = +144;
Δ = b2-4ac
Δ = -362-4·2·144
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12}{2*2}=\frac{24}{4}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12}{2*2}=\frac{48}{4}
=12
$