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(12-2x)(5-2x)=30
We move all terms to the left:
(12-2x)(5-2x)-(30)=0
We add all the numbers together, and all the variables
(-2x+12)(-2x+5)-30=0
We multiply parentheses ..
(+4x^2-10x-24x+60)-30=0
We get rid of parentheses
4x^2-10x-24x+60-30=0
We add all the numbers together, and all the variables
4x^2-34x+30=0
a = 4; b = -34; c = +30;
Δ = b2-4ac
Δ = -342-4·4·30
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-26}{2*4}=\frac{8}{8} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+26}{2*4}=\frac{60}{8} =7+1/2 $
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