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(12-3)+6x=12-(5x-8x)
We move all terms to the left:
(12-3)+6x-(12-(5x-8x))=0
We add all the numbers together, and all the variables
6x-(12-(-3x))+9=0
We calculate terms in parentheses: -(12-(-3x)), so:We get rid of parentheses
12-(-3x)
determiningTheFunctionDomain -(-3x)+12
We get rid of parentheses
3x+12
Back to the equation:
-(3x+12)
6x-3x-12+9=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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